Question

Resistance of a conductivity cell filled with a solution of an
electrolyte of concentration 0.1 M is 100 ????. The conductivity
of this solution is 1.29 S m⁻¹. Resistance of the same cell
when filled with 0.02 M of the same solution is 520 ????. The
molar conductivity of 0.02 M solution of electrolyte will be
(a) 1.24 × 10⁻⁴ S m² mol⁻¹ (b) 12.4 × 10⁻⁴ S m² mol⁻¹
(c) 124 × 10⁻⁴ S m² mol⁻¹ (d) 1240 × 10⁻⁴ S m² mol⁻¹

Answer 1

The molar conductivity of 0.02 M solution of electrolyte will be  124 x 10^-4 sm^2 / mol.

Option (C) is correct.

Explanation:

Resistant conductivity R1 = 100 ohm

K = 1.29 Sm-1

Cell come out G*  = R.K = 100 x 1.29 = 129 m-1

Same cell resistance R2 = 520 ohm

So conductivity = G* / R

K = 129 m-1 / 520 = 0.2480769  Sm-1

Molar conductivity = K / C

Molar conductivity = 0.2480769  Sm-1 /0.02 x 10^3 mol/m^3

= 124 x 10^-4 sm^2 / mol

Thus the molar conductivity of 0.02 M solution of electrolyte will be

124 x 10^-4 sm^2 / mol.

Also learn more

The resistance of 0.01M KCL solution is 200 ohms. Calculate the specific conductivity and molar conductivity if the cell constant is equal to unity  ?

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