Molar heat capacity of water in equilibrium with ice at constant pressure is
Answers
Answered by
26
The temperature of water in equilibrium with ice can be 0 deg. C.
Molar heat capacity is specific heat capacity multiplied by molecular weight.
Specific heat capacity is the heat energy required to increase the temperature of 1 gm of water.
Suppose you have x moles of ice and y moles of water liquid in equilibrium. Then initially, the ice will fuse with all the heat available to the combination. The temperature does not rise.
Heat required for ice to become water at 0 deg C = x * latent heat of fusion
= x moles * 333.55 J /gm * 18 gm/mole = x * 6,003.9 J
Heat energy required for increase in temperature now for all x+y moles :
= (x+y)*75.327 J/degK
Then, molar heat capacity = [ 6,003.9 x + (x+y)* 75.327 J/degK * ΔT] / (x+y) ΔT
Suppose x = y , that means, ice and water are present in equal proportions, then,
molar heat capacity = heat needed to increase temperature by unit degree K
= [ 6,003.9 + 2 * 75.327 * ΔT ] / 2 * ΔT
If ΔT = 1 deg K, then
= 3,077.277 Joules/mol
Molar heat capacity is specific heat capacity multiplied by molecular weight.
Specific heat capacity is the heat energy required to increase the temperature of 1 gm of water.
Suppose you have x moles of ice and y moles of water liquid in equilibrium. Then initially, the ice will fuse with all the heat available to the combination. The temperature does not rise.
Heat required for ice to become water at 0 deg C = x * latent heat of fusion
= x moles * 333.55 J /gm * 18 gm/mole = x * 6,003.9 J
Heat energy required for increase in temperature now for all x+y moles :
= (x+y)*75.327 J/degK
Then, molar heat capacity = [ 6,003.9 x + (x+y)* 75.327 J/degK * ΔT] / (x+y) ΔT
Suppose x = y , that means, ice and water are present in equal proportions, then,
molar heat capacity = heat needed to increase temperature by unit degree K
= [ 6,003.9 + 2 * 75.327 * ΔT ] / 2 * ΔT
If ΔT = 1 deg K, then
= 3,077.277 Joules/mol
kvnmurty:
click on thank you link and select best answer
Answered by
101
infinity
Explanation:
∆H=Cp ∆T
as for equilibrium ∆T =0
& ∆H can't be zero for water ice equilibrium so Cp is infinity
Similar questions