Molar heat of combustion of ethyl alcohol at constant pressure and at 300K is
- 320 K.Cal. Calculate molar heat of combustion of ethyl alcohol at constant
volume.
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Explanation:
Heat of formation of ethanol = 2× heat of formation of CO
2
+ 3× heat of formation of water - heat of combustion of ethanol
Heat of formation of ethanol = 2∗(−94)+3∗(−68.4)−(−327) = −66.2kcal
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