Molarity of 1 kg solution of 80% h2so4 (w/w) is
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How many grams of H2SO4 are in the 1L? 1.80 g/mL * 1000 mL * 0.8.= 1440 g.
Molarity = mol/L. Moles H2SO4 = 1440 g / 98.08 g/mol = 14.7. Molarity = 14.7 mol / 1 L = 14.7 M.
Molarity = mol/L. Moles H2SO4 = 1440 g / 98.08 g/mol = 14.7. Molarity = 14.7 mol / 1 L = 14.7 M.
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