molarity of 98% by mass of H2SO4 whose density is 1.8 gm/ml
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Molecular mass of H2SO4 is 98g
Density=1.8(Given)
As u know Density=Mass/Volume
Volume= Mass/Density
Volume=98/1.8=54.44ml
Molarity=Moles of solute/Vol. in ml * 1000
Moles of solute = Given mass/ Molecular mass
98% of 98 is 96.04
so moles of solute = 96.04/ 98 = 0.98
So molarity = 0.98/54.44*1000 = 0.018*1000= 18
I hope it is helpfull for u..☺
Density=1.8(Given)
As u know Density=Mass/Volume
Volume= Mass/Density
Volume=98/1.8=54.44ml
Molarity=Moles of solute/Vol. in ml * 1000
Moles of solute = Given mass/ Molecular mass
98% of 98 is 96.04
so moles of solute = 96.04/ 98 = 0.98
So molarity = 0.98/54.44*1000 = 0.018*1000= 18
I hope it is helpfull for u..☺
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