Question

molarity of acetic acid containing 6g of acetic acid per litre of solution

Answer 1

MOLARITY(M) = mols of solute / volume of solution in Litre

mols of acetic acid = given mass/molar mass
=6/60 = 0.1 mols
M=0.1 mols/1 Litre
=0.1 Molar aqueous solution .

Answer 2

Answer:

MOLARITY(M) = mols of solute / volume of solution in Litre

mols of acetic acid = given mass/molar mass

=6/60 = 0.1 mols

M=0.1 mols/1 Litre

=0.1 Molar aqueous solution .