molarity of acetic acid containing 6g of acetic acid per litre of solution
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Answered by
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MOLARITY(M) = mols of solute / volume of solution in Litre
mols of acetic acid = given mass/molar mass
=6/60 = 0.1 mols
M=0.1 mols/1 Litre
=0.1 Molar aqueous solution .
mols of acetic acid = given mass/molar mass
=6/60 = 0.1 mols
M=0.1 mols/1 Litre
=0.1 Molar aqueous solution .
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Answered by
2
Answer:
MOLARITY(M) = mols of solute / volume of solution in Litre
mols of acetic acid = given mass/molar mass
=6/60 = 0.1 mols
M=0.1 mols/1 Litre
=0.1 Molar aqueous solution .
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