Molarity of an 0.6N aluminium sulphate is
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Explanation:
Technically one must know the reaction involved; however, in problems like this the usual way of answering is M = N x positive or negative charge. For Al2(SO4)3 that is 2*3 = 6; therefore,
M = N x valence = 0.6 x 6 = 3.6
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