Question

Mole fraction of dilute acetic acid is 0.6 then find the moles of water 108gm of solution

Answer 1

Answer:

There is 1 mole of water in the solution.

Explanation:

Let the mass of acetic acid in the solution be x and mass of water in solution be y.

x + y = 108 g...(1)

Given : Mole fraction of acetic acid = 0.6

$0.6=\frac{\frac{x}{60 g/mol}}{\frac{x}{60 g/mol}+\frac{y}{18 g/mol}}$...(2)

Solving for x anf y

we get , x =90 g, y = 18 g

Moles of water =$\frac{18 g}{18 g/mol}=1 mol$

There is 1 mole of water in the solution.