Mole fraction of ethanol in aq. solution is 0.4,
molality of solution is
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Answer:
37.03 m
Explanation:
Mole fraction of ethanol in aq. solution= 0.4 (given)
n₁= moles of ethanol
n₂= moles of water
0.4= n₁/n₁+n₂
4/10= n₁/n₁+n₂
n₁=4 and n₂= 10-4= 6
Molality (m)= moles of solute/1 kg of solvent
Solvent= 6 moles*18 gm/mol
= 108 gms
= 0.108 kg
m= 4/.108
= 37.03 m
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