Question

Mole fraction of glycerine in solution of 36g of water nd 46g of glycerine

Answer 1

as we know that the formula for mole fraction is

mole fraction= moles of solute/total moles of solution.......(1)

in given data we have

we have to find the mole fraction of glycerin which can be obtained by

mole fraction= no.of mole of glycerin/no.of mole of glycerin + no.of mole of water

in given we have glycerin= 46g convert it first in moles

mole of glycerin= mass in g/molar mass of glycerin

molar mass= 92g/mol

mass=46g

mole= 46/92 = 0.5mole

now calculate  same to get moles of water

mole of water = 36/18 = 2mole

now put these values in (1)

mole fraction of glycerin = 0.5/0.5+2  = 0.5/ 2.5  = 0.20

so the mole fraction of glycerin in given solution is 0.20.

Answer 2

weight of water , w = 36g

molar weight of water {e.g., H2O} = 1 × 2 + 16 = 18g/mol

so, number of mole of water = given weight/Mol wt.
= 36/18 = 2

given weight of glycerine = 46g

molar mass of glycerine {e.g., C3H8O3} = 92g/mol

so, number of mole of glycerine = given weight/Mol wt.
= 46/92 = 0.5

mole fraction of glycerine = number of mole of glycerine/(number of mole of glycerine + number of mole of water)

= 0.5/(2 + 0.5)

= 0.5/2.5 = 1/5

= 0.2