Mole fraction of I2in CCl4 is0.2then the value of molality
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➡Let the solution be x molal.
Moles of benzene present in 1000g of benzene =
78
1000
=120.82.
Mole fraction of solute =
x+12.82
x
=0.2=
x+12.82
x
.
On solving for x we get x=3.2.....
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