Question

Mole fraction of solute in 10precent W/w aqueous NAOH solution is

Answer 1

Mass percent of NaOH = 10 ie 10g NaOH in 100g solution

mass of solvent(water) = 100 - 10 = 90g

Moles of NaOH = Given mass/Molar mass = 10/40 = 0.25 mol

Moles of H2O = Given mass/Molar mass = 90/18 = 5 mol

Mole fraction of solute(NaOH) = no. of moles of NaOH/Total no. of moles in solution = 0.25/5.25 = 0.048