Question

Mole fraction of solute in aqueous solution of 30%
NaOH is
(1) 0.16
(2) 0.05
13) 0.25
(4) 0.95​

Answer 1

Answer:

If 30% is mass percentage of NaOH in an aqueous solution then,

NaOH has molar mass 40(Na-23+O-16+H-1). 30% means 30 g of NaOH present in100 mL solution,so amount of solvent is 70 g,

Now

number of moles of NaOH is 30/40 = 0.75,

while number of moles of H2O is 70/18 = 3.89

Total number of moles 0.75 + 3.89 = 4.64

Mole fraction of NaOH will be 0.75/4.64= 0.1616

hope it helps and mark as branilist please