Question

mole fraction of solvent in 0.2 m binary aqueous solution of camphor (m equals to molality) is​

Answer 1

Answer:

Molality = moles of solute/kg solvent; Molar Mass H2O=40 g/kg = (0.8 x40)/1000 = 0.032 Molality = 0.2/0.032 = 6.25.

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