Question

Mole fraction of solvent in aqueous solution of NaOH having molality equal to 4 is

Answer 1

Molality = (No. of mole)/(Mass of solvent in kg)

4 = 4 mole of NaOH / 1 kg of H2O -------> As it is aqueous.

= 4 mole of NaOH / 1000 g of H2O

18 g of H2O => 1 mole of H2O

1000 g of H2O => ?

1000 g of H2O = 1000/18 = 55.55 mole of H2O

Mole fraction = (No. of mole of NaOh) / [(No. of mole of NaOH) + (No. of mole of H2O)]

Mole fraction = (4) / [4 + 55.55]

= 4/59.55

Therefore, Mole Fraction = 0.0671

Hope this helps! :)

Answer 2

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☆ Molality (m) is defined as the number of moles of solute per kilogram of solvent.

☆ Molarity is a measurement of the moles in the total volume of the solution, whereas molality is a measurement of the moles in relationship to the mass of the solvent.