Chemistry, asked by sameerahmed8891, 1 year ago

Mole fraction of the component 'A' in vapour phase is X and mol fraction of component 'A' in liquid mixture is Y (P0A=vapour pressure of pure A,P0A=vapour pressure of pure B) then total vapour of the liquid mixture is

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Answered by nileshdebnath2009
18

Answer:

Mole fraction of the component A in vapour phase is x1 and mole fraction of component A in liquid mixture is x2 , then ( p0A= vapour pressure of pure A ; p0B= vapour pressure of pure B ), the total pressure of liquid mixture is: (A) p0Ax2x1.

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