The vapour pressure of a pure liquid A is 80 mmHg at 300K.It forms an ideal solution with liquid B.When the mole fraction of B is 0.4,the total pressure was found to be 88 mmHg.The vapour pressure of liquid A would be
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The vapor pressure of a pure liquid A is 80 mmHg at 300K.It forms an ideal solution with liquid B. When the mole fraction of B is 0.4,the total pressure was found to be 88 mmHg. The vapor pressure of liquid B would be?
Answer:
The vapor pressure of liquid B would be .
Explanation:
Given: Vapor pressure of pure liquid A,
Total vapor pressure of solution ,
Consider is the vapor pressure of pure liquid B
Mole fraction of B,
We know
According to Raoult's law:
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