Question

Mole fraction of urea in water is 0.02. The molality of solution is


1.134


2.79


8.75


6.93

Answer 1

Answer:

Explanation:

= 0.98 X 1

= 0.98

So, mass of urea present in solution will be = number of moles of urea X molar mass of urea

= 0.02 X 60

= 1.2g

Similarly mass of water present in the solution will be = number of moles of water X molar mass of water

= 0.98 X 18 = 17.64g

Now, molality of a solution is given by the following relation

molality = number of moles of solute / Mass of solvent (in Kg)

So, molality of urea solution will be = 0.02 / 0.0176

= 1.134 m

pls mark me as brainliast

Answer 2

Explanation:

Please follow me and mark brainieliest