mole fraction of water in aqueous solution of glucose is 0.997 then what will be molarity.......
please solve this .....
Kaira1111:
Can you give some more information like number of moles of water or mass of water and volume of solution?
no
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Hello!
(XA x 1000)/ (XB x mol.wt. of B) = molality ‘m’
XB = 1 - XA
XB = Mole fraction of water.
XA = Mole fraction of Glucose
1 - 0.997 = XB
XB = 0.003
m = 0.003 × 1000 / 0.997 × 18
m = 0.167
Molality is 0.167
(XA x 1000)/ (XB x mol.wt. of B) = molality ‘m’
XB = 1 - XA
XB = Mole fraction of water.
XA = Mole fraction of Glucose
1 - 0.997 = XB
XB = 0.003
m = 0.003 × 1000 / 0.997 × 18
m = 0.167
Molality is 0.167
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