Chemistry, asked by nisha1674, 4 days ago

Mole of oxygen present in 31 g calcium phosphate is
04 mol
0.2 mol
0.8 mol
01 mol​

Answers

Answered by ay8076191
1

Explanation:

hlo mate here's your answer

0.8 mol is your answer I hope its help you

Answered by shrutimishra561810
1

Mole of oxygen in 31gm of phosphate is 0.8mole

Ca3(po4)2 =310gm

moles of calcium phosphate would be = 31/310 = 0.1mole

as one mole of calcium phosphate here contains  8 mole pf oxygen as 8 atoms of oxygen is there in compound

therefore 0.1 mole of calcium phosphate would contain 0.8 mole of oxygen  

PHOSPHATE MASS =31gm

CALCIUM =40gm

OXYGEN WOULD BE= 16gm

hence answer of this question would be 0.8 mole which is ( option 3rd ).

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