Question

Moles of Na+ions present in 500 cm3 of 0.25 M Na2SO4 solutions are:
(A) 0.25
(C) 0.375
(B) 0.125
(D) 0.5​

Answer 1

Answer:

(B) 0.125

Explanation:

1000cm3 1 M Na2SO4= 1mol Na2SO4

500 cm3 0.25 M Na2SO4 = (500×0.25)/1000

= 0.125 mol Na2SO4

Answer 2

B) 0.125

Hope it helps you