moles of oxygen atoms present in 0.1mole of FeSO4(NH4)2SO4.6H2O is
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Answered by
14
Dear Student,
◆ Answer -
Moles of O-atoms = 1.4 mol atoms
◆ Explaination -
No of oxygen atoms present in FeSO4(NH4)2SO4.6H2O is -
O-atoms/compound = 4 + 4 + 6
O-atoms/compound = 14 atoms/compound
Hence, no of O-atoms present in 0.1 mol of FeSO4(NH4)2SO4.6H2O will be -
Moles of O-atoms = moles of compound × O-atoms/compound
Moles of O-atoms = 0.1 × 14
Moles of O-atoms = 1.4 mol atoms
Hope this helps you...
Answered by
1
Answer:1.4
Explanation:
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