Question

moles of oxygen atoms present in 0.1mole of FeSO4(NH4)2SO4.6H2O is ​

Answer 1

Dear Student,

◆ Answer -

Moles of O-atoms = 1.4 mol atoms

◆ Explaination -

No of oxygen atoms present in FeSO4(NH4)2SO4.6H2O is -

O-atoms/compound = 4 + 4 + 6

O-atoms/compound = 14 atoms/compound

Hence, no of O-atoms present in 0.1 mol of FeSO4(NH4)2SO4.6H2O will be -

Moles of O-atoms = moles of compound × O-atoms/compound

Moles of O-atoms = 0.1 × 14

Moles of O-atoms = 1.4 mol atoms

Hope this helps you...

Answer 2

Answer:1.4

Explanation: