Question

moment of force of (2i+3j+4k)N acting at (3i+4j+5k) about the point (i+2j+3k) is

Answer 1

Answer:

Resultant force is, F=(i+2j−3k)+(2i+3j+4k)+(−i−j+k)=2i+4j+2k

And

r

=

AP

=−i+3j+2k

Thus vector moment about A is,

r

×F=

∣

∣

∣

∣

∣

∣

∣

∣

i

−1

2

j

3

4

k

2

2

∣

∣

∣

∣

∣

∣

∣

∣

=−2i+6j−10k

Explanation:

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