Question

Moment of inertia of a uniform cylinder of mass M and radius R about its geometric axis

Answer 1

$I_{solid\ cylinder}$=$\frac{MR^2}{2}$

$I_{hollow\ cylinder}$=$MR^2$

Explanation:

• Moment of inertia of a uniform cylinder about its geometric axis is same as that of a solid disc of  same mass and radius.

If M=mass ,R=radius,

$I_{solid\ cylinder}$=$\frac{MR^2}{2}$

• While in case of hollow cylinder

Moment of inertia of a hollow cylinder about its geometric axis is same as that of a ring of same mass M  and radius R.

$I_{hollow\ cylinder}$=$MR^2$