Two glass bulbs of equal volume are connected by a narrow tube and are filled with a gas at 0°C at a pressure of 76 cm of mercury. One of the bulbs is then placed in melting ice and the other is placed in a water bath maintained at 62°C. What is the new value of the pressure inside the bulbs? The volume of the connecting tube is negligible.
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Answer:
1.89,3.89 atm
Explanation:
Conserve no of mole
N=2*pv/r*273
Similarly
N=(1+x)v/r*300+(1-x)v/r*335
Note i have taken t=300 where ice melt
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