Question

moment of inertia of sphere about its axis is proportional to​

Answer 1

Answer:

Derivation of moment of inertia of an uniform solid sphere

Explanation:moment of inertia of sphere

An uniform solid sphere has a radius R and mass M. calculate its moment of inertia about any axis through its centre.

Note: If you are lost at any point, please visit the beginner’s lesson or comment below.

First, we set up the problem.

   Slice up the solid sphere into infinitesimally thin solid cylinders

   Sum from the left to the right

Recall the moment of inertia for a solid cylinder:

I=12MR2

Hence, for this problem,

dI=12r2dm

Now, we have to find dm,

dm=ρdV

Finding dV,

dV=πr2dx

Substitute dV into dm,

dm=ρπr2dx

Substitute dm into dI,

dI=12ρπr4dx

Now, we have to force x into the equation. Notice that x, r and R makes a triangle above. Hence, using Pythagoras’ theorem,

r2=R2–x2

Substituting,

dI=12ρπ(R2–x2)2dx

Hence,

I=12ρπ∫−RR(R2–x2)2dx

After expanding out and integrating, you’ll get

I=12ρπ1615R5

Now, we have to find what is the density of the sphere:

ρ=MV

ρ=M43πR3

Substituting, we will have:

I=25MR2

And, we’re done!

Answer 2

Answer:

solid sphere I= 2/5MR^2

hollow sphere or spherical shell I= 2/3MR^2

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