Physics, asked by sagarsingh980, 10 months ago

Momentum of a body changes from 6 kg m/s to 20 kgmps in 5 sec. Find average force acting on
the body.​

Answers

Answered by raj8000
0

Answer:

0.8

Explanation:

f=dp/dt

f=4/5=0.8

Answered by muscardinus
3

The average force acting on the body is 2.8 N

Explanation:

Given that,

Initial momentum of the body, p_i=6\ kg-m/s

Final momentum of the body, p_f=20\ kg-m/s

Time, t = 5 s

We need to find the average force acting on the body. It can be calculated using second law of motion. The rate of change of momentum is equal to the average external force such that,

F=\dfrac{p_f-p_i}{t}

F=\dfrac{20-6}{5}

F = 2.8 N

So, the average force acting on the body is 2.8 N. Hence, this is the required solution.

Learn more,

Second law of motion

https://brainly.in/question/979947

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