Question

Momentum P1=6 kg m/s and momentum P2=6 kg m/s. if added together will produce a resultant R = 5 kg m/s, Calculate the angle a between the two momentum​

Answer 1

Explanation:

As no external force is present in our system.

So Momentum is conserved:

Momentum of particleP=30×2=60

Momentum of particleQ=40×2=80

Resultant of Momentum of particle P and Q will be equal to Momentum of particle R

So,

∣R∣=∣P+Q∣=(60)2+(80)2+2PQcos90

∣R∣=100

∣mv∣=100

∣v∣=50m/s

To find angle between P and R

So, again the resultant of P and R will be equal to Q

Let the angle between P and R be θ

Therfore

∣Q∣2=∣P∣2+∣R∣2 +2PRcosθ

1600=900+2500+2×1500×cosθ

then

cosθ=−(0.6)

θ=127°

I hope it will help you thank you ❤️