Mona got 2 dresses for 1648 she is sold one at the profit of 15% and other at loss of 9% if she got the same amount for each dress then find the cost price of each of the dresses
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Given :-
2 dresses for 1648 she is sold one at the profit of 15% and other at loss of 9% if she got the same amount for each dress.
To find :-
The cost price of each of the dresses.
Solution :-
Let,
X is the price of first dress.
cost of second dress is (1648 - X)
Selling price of first dress = X x 115/100 (selling price = cost of dress 100% + profit 15%)
Selling price of second dress = (1640 - X) x 91/100 (selling price = cost of dress 100% - loss 9%)
Selling price of 1st dress = Selling price of second dress
X x 115/100 = (1648 - X) x 91/100
115X/100 = 1648 x 91 - 91X/100
115X + 91X = 1648 x 91
206X = 1648 x 91
206X = 149,968
X = 149,968÷206
X = 728
Hence, Cost of first dress
= Rs. 728
Cost of second dress = 1648 - 728
= Rs.920
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