Math, asked by piyush3453, 1 year ago

monika was 4 times as old as her son. after 16 years she will be twice as old as her son.f ind her son's present age

Answers

Answered by Anonymous
3

Let Monika's present age be x.

Her son's age is=x/4

After 16 years,Monika's age will be x+16

Her son'age will be x/4+16

=x+64/4

ATP,

x+16=2(x+64)/4

=2x+32=x+64

=x=32

x/4=32/4=8

Thus Monika's son's age is 8.

Thanks.


piyush3453: chota packet bada dhamaka. thankyou good speed
piyush3453: ok
Answered by Anonymous
4
Let the present age of Monika be x yrs
And the present age of son be y yrs
ATQ
x=4y - - - - - - - - - - - - - - - i

After 16 years
Monika s age = (x+16) yrs
Son's age = (y+16) yrs
(x+16) = 2(y+16)
x+16=2y+32
=> x-2y-16=0 - - - - - - - - - - - - - - ii

Substituting the value of x from i to ii

4y-2y = 16
=> 2y=16
=> y=8

x=4y
=4x8
= 32

Therefore, present age of Monika is 32 years
And the present age of Son is 8 years





HOPE IT HELPS YOU !!!!!
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