monochromatic light of wavelength lemda = 450nm illuminates the two slits of young experiment having sepration 0.15mm. the screen is placed at a distance of 1.0m from the slitsc. find the sepration of second bright fringe from the seventh dark fringe on the screen
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Answer:
a)1)
y=
d
nλD
=2×
0.15×10
−3
450×10
−9
×1
=6×10
−3
m
=6mm
2)
y=(2n−1)
2d
λD
=(2×2−1)×
2×0.15×10
−3
450×10
−9
×1
=4.5mm
b) as D increases, fringe width β as β∝D
Best angular separation(=
d
π
) remains constant.
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