Question

monochromatic light of wavelength lemda = 450nm illuminates the two slits of young experiment having sepration 0.15mm. the screen is placed at a distance of 1.0m from the slitsc. find the sepration of second bright fringe from the seventh dark fringe on the screen​

Answer 1

Answer:

a)1)

y=

d

nλD

=2×

0.15×10

−3

450×10

−9

×1

=6×10

−3

m

=6mm

2)

y=(2n−1)

2d

λD

=(2×2−1)×

2×0.15×10

−3

450×10

−9

×1

=4.5mm

b) as D increases, fringe width β as β∝D

Best angular separation(=

d

π

) remains constant.