Mother is 25 years older than her son. Find son's age if after 8 years ratio of son's age to mother's age will be 4/9.
Answers
Answered by
61
Answer:
Son's age = 12 years
Mother's age = 27 years
Step-by-step explanation:
Let the son's age be x years
Let his mother's age be x + 25 years
After 8 years, age of son = x + 8 and age of mother = x + 25 + 8 = x + 33 years
According to the question,
=
=> 9(x + 8) = 4(x + 33)
=> 9x + 72 = 4x + 132
=> 9x - 4x = 132 - 72
=> 5x = 60
=> x =
=> x = 12
Present age of son is x years
=> 12 years
Present age of mother is x + 25 years
=> 12 + 25
=> 37 years
Answered by
33
HEY MATE HERE IS YOUR ANSWER
Let the age of son be y
Mother age be y + 25
After 8 years
Age of son = y + 8
Mother age = y + 25 + 8 = y + 33
ATQ
➡️ (y+8)/(y+33) = 4/9
➡️ 9(y+8) = 4(y +33)
➡️ 9y + 72 = 4y + 132
➡️ 9y-4y = 132-72
➡️ 5y = 60
➡️ y= 60/5
➡️ y=12
Age of son = 12 years
. Age of his mother = y + 25 = 12 + 37
➡️ 37 years
_________________
Hope it will help you
@thanksforquestion
@bebrainly
Please please approved my answer also
Let the age of son be y
Mother age be y + 25
After 8 years
Age of son = y + 8
Mother age = y + 25 + 8 = y + 33
ATQ
➡️ (y+8)/(y+33) = 4/9
➡️ 9(y+8) = 4(y +33)
➡️ 9y + 72 = 4y + 132
➡️ 9y-4y = 132-72
➡️ 5y = 60
➡️ y= 60/5
➡️ y=12
Age of son = 12 years
. Age of his mother = y + 25 = 12 + 37
➡️ 37 years
_________________
Hope it will help you
@thanksforquestion
@bebrainly
Please please approved my answer also
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Let his mother's age be x + 25 years
After 8 years, age of son = x + 8 and age of mother = x + 25 + 8 = x + 33 years
According to the question,
\dfrac{x + 8}{x + 33}x+33x+8 = \dfrac{4}{9}94
=> 9(x + 8) = 4(x + 33)
=> 9x + 72 = 4x + 132
=> 9x - 4x = 132 - 72
=> 5x = 60
=> x = \dfrac{60}{5}560
=> x = 12
Present age of son is x years
=> 12 years
Present age of mother is x + 25 years
=> 12 + 25
=> 37 years