Question

motion in a straight line

Answer 1

i think 1 is correct ans

Answer 2

area under a curve is given by the integration of that function

Required area
$= \int\limits^1_0 { x^{2} } \, dx$

$= \frac{ x^{3} }{3} \left \{ {{1} \atop {0}} \right.$

$= \frac{ 1^{3} }{3} -0$

$= \frac{1}{3}$