Question

MOTION IN A STRAIGHT LINE
Example 3.2
The position of an object
moving along x axts is given by a + b
where a = 8.5 m. b = 2.5 ms and is
measured in seconds. What is its velocity at
t=0 s and t = 2.0 s. What is the average
velocity between t=2.0 s and t = 4.0 s?
Answer In notation of differential calculus, the​

Answer 1

Answer:

Position is given as   x=a+bt2=8.5+2.5t2

Position at t=2 s,  x2=8.5+2.5(2)2=18.5 m

Position at t=4 s,   x1=8.5+2.5(4)2=48.5 m

Displacement  S=x2−x1=48.5−18.5=30 m

Time taken  t=4−2=2 s

Average velocity  Vavg=tS=230=15 m/s