Question

motion in straight line

Answer 1

Hola User____________

Here is Your Answer....!!!!!
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☆ Actually welcome to the concept of Kinematics and the motion of the bodies....

☆Basically by using the ....third equation of motion we get here as....

☆Given ...., u= 10 m/s , v= 20 m/s and g = 10 m/s^2.....

☆so here we get ....

v^2 = u^2 - 2gh....

☆thus (20)^2 = (10)^2 -2(10)h .....

==> 400 = 100 -20h ...

☆thus 300 = -20h ....
☆ there fore h = 15 metres .....

☆Thus the height of the tower is 15 m....

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Hope it helps u......☺