History, asked by loge43, 1 year ago

motor boat starting a lake acceleration in a straight line at constant rate of 3.0ms-2 from 8.0s how far does the boat travel during this time

Answers

Answered by Yashumishra

u= 0
a= 3
t=8
s=?
s=ut+1/2xat^2
s=0x8+1/2x3x(8)^2
s=1/2x3x64
s=3×32
s=96m

loge43: plzz explain mam

Yashumishra: Inital Velocity (U) =0 (bcoz body starts from rest) Time(t) =8 seconds Acceleration (a)= 3 And Then Put 2nd Equation Of Motion i.e S=UxT +1/2 Ax(T)^2

loge43: then why we should put s=u×t+1/2ax (t)^2 mam

Yashumishra: Because We Need To Find Distance i.e S so we put it

loge43: k mam thats it mam then then the answer will be 96m

Yashumishra: Yes

loge43: k mam thank you mam

Yashumishra: understood now?

loge43: s mam

Yashumishra: Ohk

Answered by Anonymous

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}} \\$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

u = 0 [starting from rest]

t = 8 sec

a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2} \\ \\$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64) \\ \\$

$\\ : \implies \sf \: s = 32 \times 3 \: m \\ \\$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar \\ \\$

Hence ,

The distance travelled by the boat during that time is 96 m.

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