Question

Motorbike initial moving at 10 km per hour rate at rate of 5 metre per second calculate the distance covered by it from start and final velocity

Answer 1

$77.16 \: cm$

Explanation:

$Given, \: \: u = 0 \: m {s}^{ - 1} , \: \: a = 5\: m {s}^{ - 2} \\ and \: \: \: v = 10 \: km {h}^{ - 1} = 10 \times \frac{5}{18}\: m {s}^{ - 1} = \frac{25}{9} \: m {s}^{ - 1}\\ we \: \: know \: \: \boxed{ {v}^{2} = {u}^{2} + 2as } \\ Now, \: \: \: putting \: \: values \\ ( \frac{25}{9} )^{2} = (0)^{2} + 2 \times 5 \times s \\ \frac{625}{81} = 10 \times s \\ s = \frac{625}{81} \times \frac{1}{10} \\ = 0.7716 \: m \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0.7716 \times 100 \: cm \\ = 77.16 \: cm$