Physics, asked by RdShelar407, 1 day ago

Velocity vof a body changes from 2m/s to 6m/s in 2s what is the acceleration

Answers

Answered by vikkiain
1

 2\: m {s}^{ - 2}

Explanation:

Given, \:  \:  \: u = 2 \: m {s}^{ - 1} ,  \:  \: v = 6 \: m {s}^{ - 1}  \\ and \:  \:  \: t = 2s \\ we \:  \: know \:  \:  \boxed{v = u + at} \\ Now, \:  \:  \: putting \:  \: values \\6 \: m {s}^{ - 1}  = 2 \: m {s}^{ - 1}  + a \times 2s \\ 6 \: m {s}^{ - 1} -  2 \: m {s}^{ - 1}   = a \times 2s \\ 4 \: m {s}^{ - 1}  = a \times 2s \\ \frac{4}{2}  \: m {s}^{ - 2}  = a \\ 2 \: m {s}^{ - 2}  = a \\  \boxed{a = 2 \: m {s}^{ - 2} }

Similar questions