motorcycle moving with a speed of 5 M per second in subjected to an acceleration of 0.2 metre per second square calculate the speed of the motor cycle after 10 second and the distance travelled in the this time
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u=5m/s
a=0.2m/s^2
t=10s
v=0
s=ut+1/2 at^2
s=(5)(10)+1/2(0.2)(10)^2
s=50+10
s=60m
speed =distance/time=60/10
speed =6m/s
a=0.2m/s^2
t=10s
v=0
s=ut+1/2 at^2
s=(5)(10)+1/2(0.2)(10)^2
s=50+10
s=60m
speed =distance/time=60/10
speed =6m/s
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