any one who can solve........
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m = 140 gm = 0.14 kg ,v1 = 39 m/s ,v2 = -39 m/s
F = m(v1 - v2)/∆t
= 0.14[39 -(-39)] / (1.2 x 10^-3)
= 1400 x 78 / 12
= 9100 N
i hope it will help you
regards
F = m(v1 - v2)/∆t
= 0.14[39 -(-39)] / (1.2 x 10^-3)
= 1400 x 78 / 12
= 9100 N
i hope it will help you
regards
shivam8899:
is it correct bro?
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