Question

mounika's present age is 2 times of her sister. After 5 years she will be 2 years older than her sister. Then the present age of mounika is

Answer 1

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Let Mounika's age be 'x',

Her sister's age be 'y',

$x = 2y --(1)$

5 years later,

$x+5 = y + 5 + 2$

$x+5 = y + 7 --(2)$

Sub (1) in (2),

$2y + 5 = y + 7$

$2y + 5 - y - 7 = 0$

$y - 2 = 0$

$y = 2$

So, mounika's present age

$=x$

$=2y$

$=2(2)$

$=4$

Answer 2

Answer:

Mounika is 4 years old and her sister is 2 years old.

Step-by-step explanation:

Given:

Mounika's current age is 2 times of her sister. After 5 years she will be 2 years older than her sister.

To find the present age of mounika.

Step 1

Apply the given conditions and find ages.

Let the age of mounika $=\mathrm{m} .$

Let the age of her sister $=\mathrm{s} .$

Given that, $\mathrm{m}=2 \mathrm{~s} .$

After 5 years, mounika will be 2 years older than her sister.

$&\Rightarrow(\mathrm{m}+5)=(\mathrm{s}+5)+2$

$&\Rightarrow \mathrm{m}=\mathrm{s}+2$

Step 2

Put, $\mathrm{m}=2 \mathrm{~s}$

$&\Rightarrow \mathrm{s}+2=2 \mathrm{~s}$

$&\mathrm{~s}=2 \text { and } \mathrm{m}=4$

Hence, Mounika is 4 years old and her sister is 2 years old.

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