Question

= movimiv
E) Displacement
148.A man fires a bullet of mass 200gm at a speed of 5m/s. The gun is of one Kg mass. By
what velocity the gun rebounds backwards?
A) 0.1 m/s
B) 0.5 m/s
C) 1 m/s
D) 0.01 m/s
C) 10 m/s
explain​

Answer 1

Answer:

Velocity of the gun = -1 m/s

Explanation:

m1 - mass of bullet = 200 g = 0.2 kg

m2 - mass of gun = 1 kg

V1 - velocity of bullet = 5 m/s

V2 - velocity of gun = ??

According to law of conservation of linear momentum,

Linear momentum=Linear momentum

before firing after firing

0 = m1 V1 + m2 V2

V2 = - m1 V1/m2

= - 0.2×5×1

V2 = - 1 m/s

Velocity of the gun = -1 m/s.

Answer 2

d is correct,...................