Question

moving with a uniform acceleration from the state of rest of a body cover 22 m during the 6 sec of its motion. what is the distance covered by if during the first 6 sec?

Answer 1

During the first 6sec it can covered distance is22meter

Answer 2

For this, we can use the formula for distance.

i.e., $S_{ n }=ut+\frac { 1 }{ 2 } at^{ 2 }$

where $S_n$ is the distance covered; u is the initial velocity of the object which is zero in this case while t is the time.

Now to find the acceleration we have been given the distance traveled in 6th second.

So, $S_{ 6 }-S_{ 5 }=\frac { 1 }{ 2 } a(62-52)$

              $22=\frac { 1 }{ 2 } \times a\times 11$

              $a=4\frac { m }{ s^{ 2 } }$

              $S_{ n }=0+\frac { 1 }{ 2 } \times 4\times 62$

              $S_{ n } = 72m$