Question

Moving with uniform acceleration, a body covers 150m during 10sec so that it covers 24m during the 10th second.. What is the initial velocity and acceleration of the body?

Answer 1

Let initial velocity of body is u and uniform acceleration is a.

distance is covered by particle in t sec, s = ut + 1/2 at²

here, t = 10sec, s = 150 m

so, 150 = u(10) + 1/2a(10)²

⇒150 = 10u + 50a

⇒15= u + 5a .......(1)

again, distance is covered by particle during nth sec, Sn = u + 1/2a(2n - 1)

here, n = 10, Sn = 24m

so, 24 = u + 1/2a(2 × 10 - 1)

⇒ 24 = u + 19a/2 .......(2)

from equations (1) and (2),

24 - 15 = u - u + 19a/2 - 5a

⇒9 = 9a/2

⇒a = 2 m/s² , putting in equation (1),

24 = u + 19 × 2/2 ⇒u = 5 m/s

hence, initial velocity = 5m/s and acceleration = 2m/s²

Answer 2

Answer:

• a. is 2 meter per second square
• u is 5 meter per second