Question

*mple 12 : Use elimination method to find all possible solutions of the following
de air of linear equations :
Оe
2x + 3y=8
(1)
4x + y = 7
(2)
$22552258255222.. {y {y2 + {x { {y}^{?} }^{?} }^{?} }^{?} }^{?}$
​

Answer 1

Answer:

No soln.

Explanation:

2x + 3y = 8  ......(1)

4x + 6y = 7   .....(2)

Step 1 : Multiply Equation (1) by 2 and Equation (2) by 1 to make the coefficients of x equal. Then we get the equations as :

4x + 6y = 16   ......(3)

4x + 6y = 7   .........(4)

Step 2 : Subtracting Equation (4) from Equation (3),

(4x – 4x) + (6y – 6y) = 16 – 7

i.e., 0 = 9, which is a false statement.

Therefore, the pair of equations has no solution.