Physics, asked by patelyash47597, 1 month ago

MPREHENSION BASED QUESTIONS MISCELLAENEOUS aprehension-1 Torque acting on a current loop in uniform magnetic field is given by -MXB. But force on it is zero. If it is free to rotate then it will rotate about an axis passing through its centre of mass and parallel to the potential energy of loop is given by U=-MB A current carrying ring with its centre at origin and moment of inertia 2 x 10kg-m' about an axis passing through its centre and perpendicular to its plane has magnetic moment M=(3-4) A-m". At time t = 0 a magnetic field B=(4+3) Tisswitched on Angular accelerañon of the ring attimet=0inrads is (A) 5000 B) 1250 (C) 2500 (D) zero Maximum angular velocity of the ring in rad s will be (A) 502 (B) 25,2 (C) 1002 (D) 150-2 rehension-2 In uniform magnetic field, if angle between 0 and B is 0º < 8< 90°, path of the partide is helix, with its axis parallel to B and plane perpendicular to B. Here v is the velocity vector of the particle and B magnetic field is given by talk equal to admin to be but force on it is zero if it is free to rotate then it will rotate about the axis passing through its centre of mass and parallel to the time the potential energy of loaf is given by you equal to minus a into b current carrying ring with its centre at origin and moment of inertia 2 into 10 ki power minus 2 kg metre square about an axis passing through its centre and perpendicular to its plan has magnetic moment m is equal to 3 and minus 4 Jacob m m square at a time t = 20 a magnetic field b equal to 4 ICAP + 3 j cap thus used on​

Attachments:

Answers

Answered by PurvanshiAttri
0

Answer:

Have you answer the question already? It's too long

Similar questions