Question

mr. A sells a bicycle to Mr. B at a profit of 20% and Mr. B sells it to Mr. C at a profit 25% . If Mr. C pays rupee 1500 , what did Mr. A pay for it?​

Answer 1

➤ Given :-

Profit percent of A :- 20%

Profit percent of B :- 25%

Cost paid by C :- ₹2500

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➤ To Find :-

Coat price of the bicycle for A.

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★ How to do :-

Here, we are given that a bicycle is sold by A to B at some profit. The same bicycle is sold by B to C. While B sold it to C, he gained some percentage. We are also given with the cost paid by C to buy the bicycle. We are asked to find the cost price of the bicycle when A buys it. So, first we should find the cost price of B by using the profit percentage and the cost paid by C to buy the bicycle. Then, we use the cost price of B and the profit percent of A and find out the cost price of Arjun. We can see that here the selling price of B is as same as the cost paid by C. So, let's solve!!

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➤ Solution :-

We know that the selling price of B is same as the cost paid by C. So,

Cost price of B :-

${\tt \leadsto \underline{\boxed{\sf \dfrac{100}{(100 + Profit \bf\%)} \times SP}}}$

Substitute the given values.

${\tt \leadsto \dfrac{100}{(100 + 25)} \times 1500}$

Write the fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{100}{125} \times 1500 = \dfrac{4}{5} \times 1500}$

Multiply the remaining numbers.

${\tt \leadsto \dfrac{4 \times 1500}{5} = \dfrac{6000}{5}}$

Write the obtained fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{6000}{5} = 1200}$

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We know that the cost price of B is same as the selling price of A. So,

Cost price of A :-

${\sf \leadsto \underline{\boxed{\sf \dfrac{100}{(100 + Profit \bf\%)} \times SP}}}$

Substitute the given values.

${\tt \leadsto \dfrac{100}{(100 + 20)} \times 1200}$

Write the fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{100}{120} \times 1200 = \dfrac{5}{6} \times 1200}$

Multiply the remaining numbers.

${\tt \leadsto \dfrac{5 \times 12000}{6} = \dfrac{6000}{6}}$

Write the obtained fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{6000}{6} = 1000}$

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${\red{\underline{\boxed{\bf So, \: the \: cost \: price \: of \: A \: is \: \: 1000.}}}}$