Mr. and Mrs. Ahuja weigh x kg and y kg respectively. They both take a dieting course , at the end of which Mr.Ahuja loses 5kg and weighs as much as his wife weighed before the course. Mrs. Ahuja loses 4kg and weighs 7/8th of what her husband weighed before the course .Form two equations in x and y ,find their weights before taking the dieting course.
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Answered by
42
for x :-
x-5kg=y
x=y+5
for y :-
y-4kg=7/8x
y-4=7/8(x=y+5)
y-4=7y+35/8
8 (y-4)=7y+35
8y-32=7y+35
8y-7y=35+32
y=67kg ( Mrs. Ahuja's weight )
again for x:-
x=y+5
x=(y=65)+5
x=67+5
x=72kg (Mr. Ahuja's weight)
x-5kg=y
x=y+5
for y :-
y-4kg=7/8x
y-4=7/8(x=y+5)
y-4=7y+35/8
8 (y-4)=7y+35
8y-32=7y+35
8y-7y=35+32
y=67kg ( Mrs. Ahuja's weight )
again for x:-
x=y+5
x=(y=65)+5
x=67+5
x=72kg (Mr. Ahuja's weight)
Answered by
5
Answer:
Mr ahuja =72kg and Mrs ahuja =67kg
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