Question

Mr. Basu is the head of department of Mathematics for secondary and senior secondary division
in his school. Under his tenure, results of classes 10 to 12 have been very impressive. It is exam
time again and he is giving instructions about seating assignments. There are 104 students in
class X and 96 students in class IX. He advised an arrangement in such a way that students are
to be evenly seated in parallel rows such that no two adjacent rows are of the same class.
Based on above situation, answer the following questions :
(i) Find the maximum number of parallel rows of each class for the seating arrangement
(ii) Also find the number of students of class IX and also of class X in a row.
​

Answer 1

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Answer 2

13 Rows of Class X , & 12 Rows for Class IX ,  number of students of class IX and also of class X in a row = 8

Step-by-step explanation:

There are 104 students in class X and 96 students in class IX.

so arrangement should be like this

Class X has one extra row  ( start with class X & end with Class IX)

Let say class X rows = N

then Class IX rows = N - 1

104/N  = 96/(N - 1)

=> 104N - 104 = 96N

=> 8N = 104

=> N = 13

13 Rows of Class X

& 12 Rows for Class IX

number of students of class IX and also of class X in a row = 8

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