Question

Value of (1-w+w^2)^5+(1+w-w^2)^5 is
​

Answer 1

Answer:

∴w is cube root of unity

∴w

3

=1 and 1+w+w

2

=0

(1+w+w

2

)

5

+(1+w−w

2

)

5

=(0)

5

+(−w

2

−w

2

)

5

=(−2w

2

)

5

=−32w

10

=−32(w

3

)

3

.w

=−32w